Question

What is the volume of the gas if there are 3.20 mol of gas at 265 K and 2.50 atm of pressure?

Answer 1

Answer:

27.81 L

Explanation:

Assuming the gas is ideal, we can solve this problem by using the following formula:

• PV = nRT

Where:

• P is Pressure, 2.50 atm

• V is Volume

• n is the number of moles, 3.20 mol

• R is a constant, 0.082 atm·L·mol⁻¹·K⁻¹

• T is temperature, 265 K

We input the data:

• 2.50 atm * V = 3.20 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 265 K

And solve for V:

• V = 27.81 L