Question

What is the mass, in grams, of a piece of aluminum if its temperature changes from 25.0 ºC to 31.5 ºC when it absorbs 42.2 joules of energy? The specific heat for aluminum is 0.89J/gºC

Answer 1

Answer:

m = 7.29 grams

Explanation:

Given that,

Initial temperature, T₁ = 25ºC

Final temperature, T₂ = 31.5ºC

The specific heat of the metal is 0.89 J/gºC.

We know that the heat released due to the change in temperature is given by :

$Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g$

So, the mass of the piece is equal to 7.29 grams.