Question

What is the standard equation of a circle with a center of (-3,5) and a radius of 2?

Answer 1

Answer:

A circle whose center is located at point (a, b) having a radius of length r has the equation:

(x -a)² + (y -b)² = r²

(x - -3)^2 + (y -5)^2 = 2^2  =

x^2 +6x + 9 + y^2 -10y +25 =4

Step-by-step explanation: