Given :
A cylinder of Krypton has contains 17 L of Ar at 22.8 atm and 112 degrees Celsius.
To Find :
How many moles are in the cylinder.
Solution :
We know, by ideal gas equation :
[tex]PV = nRT\\\\n = \dfrac{PV}{RT}[/tex]
Here, R is gas constant and [tex]R = 8.205 \times 10^{-5} \ m^3\ atm\ K^{-1} mol^{-1}[/tex]
Converting all given in required units and putting in above equation, we get :
[tex]n = \dfrac{P\times V}{ R \times T}\\\\n = \dfrac{22.8 \times 0.017}{8.205\times (112+273)}\ moles\\\\n = 1.22 \times 10^{-4} \ moles[/tex]
Hence, this is the required solution.