Answer:
Sr(NO₃)₂(aq) + Na₂CO₃(aq) ⇒ SrCO₃(s) + 2 NaNO₃(aq)
Sr²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + CO₃²⁻(aq) ⇒ SrCO₃(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)
Sr²⁺(aq) + CO₃²⁻(aq) ⇒ SrCO₃(s)
Explanation:
Let's consider the molecular equation that occurs when aqueous solutions of strontium nitrate and sodium carbonate react. This is a double displacement reaction.
Sr(NO₃)₂(aq) + Na₂CO₃(aq) ⇒ SrCO₃(s) + 2 NaNO₃(aq)
The total ionic equation includes all the ions and the insoluble species.
Sr²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + CO₃²⁻(aq) ⇒ SrCO₃(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
Sr²⁺(aq) + CO₃²⁻(aq) ⇒ SrCO₃(s)