The vertex of the parabola f(x) = 2x^2 - 4x + 6 is (1, 4)
The function is given as:
f(x) = 2x^2 - 4x + 6
Differentiate the function
f'(x) = 4x - 4
Set to 0
4x -4 =0
So, we have:
4x = 4
Divide by 4
x = 1
Substitute x = 1 in f(x) = 2x^2 - 4x + 6
f(1) = 2(1)^2 - 4(1) + 6
This gives
f(1) = 4
This means that the vertex is (1, 4)
Next, we set x = 0.
So, we have:
f(0) = 2(0)^2 - 4(0) + 6
This gives
f(0) = 6
This means that the parabola passes through the point (0, 6)
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