Question

Solve the equation:
$2 {x}^{2} + 7x - 3 = 0$
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Answer 1

Answer:

$delta = {7}^{2} - 4 \times 2 \times ( - 3) \\ = 49 + 24 = 73 \\ x 1= \frac{ - 7 + \sqrt{73} }{4} \\ x 2= \frac{ - 7 - \sqrt{73} }{4}$