Question

A sample of Chlorine gas has a volume of 20 L and a pressure of 4 atm. What will the
pressure of the gas be if the volume is decreased to 5 L?

Answer 1

Step-by-step explanation:

$from \: boyle 's \: law \\ P _{1}V _{1} = P _{2} V _{2} \\ (4 \times 20) = (P _{2} \times 5) \\ P _{2} = \frac{(4 \times 20)}{5} \\ P _{2} = 16 \: atm$