Answer:
1.49kJ
Explanation:
Using the formula as follows;
Q = m × c × ∆T
Where;
Q = amount of heat (joules)
m = mass (g)
c = specific heat of silver (J/g°C)
∆T = change in temperature (°C)
According to the information given in this question;
mass of Silver (Ag) = 236g
c of Ag = 0.24 J/g°C
initial temperature (T1) = 8.5°C
final temperature (T2) = 34.9°C
∆T = T2 - T1 = 34.9 - 8.5 = 26.4°C
Using Q = m × c × ∆T
Q = 236 × 0.24 × 26.4
Q = 1,495.3 Joules
Amount of heat needed to raise the temperature of Silver (Q) in kilojoules is 1495.3/1000 = 1.4953
Q = 1.49kJ
