Step-by-step explanation:
[tex] {x}^{2} - 5x - 2 = 0 \\ a = 1 \: and \: b = - 5 \: and \: c = - 2 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - ( - 5)± \sqrt{ {( - 5)}^{2} - (4 \times 1 \times - 2)} }{(2 \times 1)} \\ x = \frac{5± \sqrt{33} }{2} \\ either : x = \frac{5 + \sqrt{33} }{2} \: or \: \frac{5 - \sqrt{33} }{2} \\ x = 5.4 \: or \: - 0.4[/tex]
