Answer:
4x + 10
Step-by-step explanation:
Given
Let
[tex]t = time[/tex]
[tex]s = speed[/tex]
So:
[tex]t = 2; s = (2x +5)[/tex] --- first 2 hours
[tex]t = 3; s = (3x -5)[/tex] --- last 3 hours
Required
Distance covered in the first 2 hours
Distance (d) is calculated as:
[tex]Distance = speed * time[/tex]
i.e.
[tex]d = s * t[/tex]
For the first 2 hours, we have:
[tex]t = 2; s = (2x +5)[/tex]
So:
[tex]d = (2x + 5) * 2[/tex]
Open bracket
[tex]d =2x * 2 + 5 * 2[/tex]
[tex]d =4x + 10[/tex]
Hence, the distance covered in 4x + 10