Question

f(x)=7x-2 g(x)=x2+1 h(x)=3x (x at the corner of 3 ) a- find gh(2) b- find f-1(x)

Answer 1

Answer: 37, $\frac{x+2}{7}$

Step-by-step explanation:

Given

$f(x)=7x-2\\g(x)=x^2+1\\h(x)=3x$

now,

$g(h(x))=(3x)^2+1\\g(h(x))=9x^2+1$

for x=2

$g(h(2))=9\cdot (2)^2+1\\g(h(2))=36+1\\g(h(2))=37$

Inverse of $f(x)$ is given by

$y=7x-2\\x=\dfrac{y+2}{7}\\\\f^{-1}(x)=\dfrac{x+2}{7}$