Question

A student increases the temperature of a 355 cm3 balloon from 325K to 353K. What
will the new volume of the balloon be?
Charles's Law
V 부
273 cm
3
327 cm
3
353 cm 3
386 cm
3

Answer 1

Answer:

385.6cm³

Explanation:

Using Charles law equation as follows;

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 355cm³

V2 = ?

T1 = 325K

T2 = 353K

Using V1/T1 = V2/T2

355/325 = V2/353

1.092/1 = V2/353

Cross multiply

1.092 × 353 = V2

V2 = 385.6cm³