Question

Simplify the expression below. (2y+1)^2-4y^2+2

A. 4y+3
B. 2y+3
D. -1

Answer 1

Answer:

4 y + 3

Step-by-step explanation:

y = -3/4

d/dy((2 y + 1)^2 - 4 y^2 + 2) = 4

Indefinite integral:

integral(2 - 4 y^2 + (1 + 2 y)^2) dy = 2 y^2 + 3 y + constant