Question

6. If 4 mole of the rocket fuel ammonium perchlorate, NH4C/04 (s) is
allowed to react with excess Al so all of the NH4ClO4 is consumed, how
many grams of water will be produced?
3NH_CI04 (s) + 3Al (s) Al2O3 (s) + AlCl3 (s) + 3NO (g) + 6H2O (g)

Answer 1

Answer:

144g of H₂O

Explanation:

3NH₄ClO₄(s) + 3Al → Al₂O₃(s) + AlCl₃(s) + 3NO(g) + 6H₂O(g)

From the equation:

3 moles of NH₄ClO₄ produced 6 moles of H₂O

4 moles of NH₄ClO₄ produced ? moles of H₂O

(4 ₓ 6)/3 = $\frac{24}{3}$ = 8 moles of H₂O

1 mole of H₂O = (1 × 2) + 16 = 18g (The Relative Molecular mass of H₂O)

8 moles of H₂O = ?

Therefore 8 × 18 = 144g

=144g of H₂O