Question

what choices are solutions for equation x^2-3x = -5/4

Answer 1

Here's the solution,

=》

${x}^{2} - 3x = - \dfrac{5}{4}$

=》

${x}^{2} - 3x + \dfrac{5}{4} = 0$

now, let's multiply the whole equation with 4

=》

$4 {x}^{2} - 12x + 5 = 0$

=》

$4 {x}^{2} - 10x - 2x + 5= 0$

=》

$2x(2x - 5) - 1(2x - 5) = 0$

=》

$(2x - 1)(2x - 5) = 0$

so,

Case 1. where, 2x - 5 = 0

=》

$x = \dfrac{5}{2}$

case 2. where, 2x - 1 = 0

=》

$x = \dfrac{1}{2}$