Answer:
z=-3 so 2y+3(-3)=-8, 2y-9=-8, add 9 to both sides 2y=1 divide both sides by 2, y=1/2, so 3x+4(1/2)+-3=-2, 3x+2-3=-2, 3x-1=-2, add 1 to both sides, 3x=-1, divide both sides by 3, x=-1/3
y = 1/2
x = -1 / 3
z = -3
Step-by-step explanation:
In this question, in order to find "y" and "x", we do the following...
Since we know z = -3 we can find "y" by substituting z in the second equation.
2y + 3z = -8
2y + 3(-3) = -8
2y - 9 = -8
2y = 1
Now we know "y" and "z" and so we can find x...
3x + 4y + z = -2
3x + 4(1/2) - 3 = -2
3x + 2 - 3 = -2
3x = -1
