Question

Limestone has a density of 2.72 g/cm3. What is the mass of 8.92 cm3 of limestone?

Answer 1

it should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
hope this helped :)

Answer 2

Answer:

$\boxed {\boxed {\sf 24.2624 \ g}}}$

Explanation:

Density measures mass per volume. The volume is

$\rho=\frac{m}{v}$

The density of limestone is 2.72 grams per cubic centimeter. We have a piece of limestone with a volume of 8.92 cubic centimeters.

• ρ= 2.72 g/cm³
• v= 8.92 cm₃

Substitute the values into the formula.

$2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}$

Now we solve for m, the mass, by isolating the variable.

m is being divided by 8.92 cubic centimeters. The inverse of division is multiplication, so we multiply both sides by 8.92 cubic centimeters.

$8.92 \ cm^3 * 2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}* 8.92 \ cm^2$

$8.92 \ cm^3 * 2.72 \ g/cm^3=m$

The units of cubic centimeters cancel out.

$24.2624 \ g =m$

The mass of this piece of limestone is 24.2624 grams.