Question

A 3mL sample of a 200 Molar solution is left open on a lab
counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?

Answer 1

Answer: New volume of the solution is 100 mL.

Explanation:

Given: $V_{1}$ = 3 mL,     $M_{1}$ = 200 M

$M_{2}$ = 6 M,     $V_2$ = ?

Formula used to calculate the new volume of solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL$

Thus, we can conclude that new volume of the solution is 100 mL.