Question

need help, I'm stuck on this​

Answer 1

Answer:

The answer is 729/64.

Step-by-step explanation:

I would first simplify the equation.

In the denominator, you can get rid of b^0 because that just equals 1.

For the a's in the numerator and denominator, you have to flip them so the exponents can be positive.

Equation:  $(\frac{3ab^2}{2a^3})^2$

Now, you can subtract a and a^3.  This would be 1/a^2.

Equation: $(\frac{3b^2}{2a^2})^2$

Now, you can square the whole equation.

Equation: $\frac{9b^4}{4a^4}$

This is the simplified equation.  Now you can plug in -2 and -3.

Equation: $\frac{9(-3)^4}{4(-2)^4}$

Equation: $\frac{9(81)}{4(16)}$

Equation: 729/64