Question

A sample of gas with a volume of 5.0 m3 at a temperature of 298 K and a pressure of 0.84 atmospheres is left in a closed container where the temperature increases to 323 K and the pressure increases to 0.89 atmospheres. What is the new volume of a gas sample?

Answer 1

Answer:

5.12 m³

Explanation:

Using the combined gas law formula as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (m³)

V2 = final volume (m³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question;

V1 = 5.0 m³

V2 = ?

P1 = 0.84 atm

P2 = 0.89 atm

T1 = 298 K

T2 = 323 K

Using

P1V1/T1 = P2V2/T2

0.84 × 5/298 = 0.89 × V2/323

4.2/298 = 0.89V2/323

Cross multiply

4.2 × 323 = 298 × 0.89V2

1356.6 = 265.22V2

V2 = 1356.6 ÷ 265.22

V2 = 5.12 m³