Answer:
The answer is "[tex]\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}[/tex]"
Explanation:
When [tex]HCI[/tex] is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:
[tex]CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\[/tex]
In this, the [tex]CH_3COOH[/tex] is a weak acid so, it not completely dissociated.
[tex]CH_3COONa \ (aq) \ \ and \ NaCl[/tex] were strong electrolytes they are completely dissociated.
The [tex]HCl[/tex] is a strong acid so, it is completely dissociated So, the net ionic equation is:
[tex]CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)[/tex]