Respuesta :
Answer:
Max: [tex]Z = 120x + 130y[/tex]
Subject to:
[tex]2x + y \le 500[/tex]
[tex]2x + 3y \le 800[/tex]
[tex]x \le 220[/tex]
[tex]y \le 180[/tex]
[tex]x,y \ge 0[/tex]
Explanation:
Given
Let:
[tex]x \to Units\ of\ full\ size[/tex]
[tex]y \to Units\ of\ compact\ size[/tex]
Required
Formulate a linear optimization model
Constraints for time:
For the general assembly (hours), we have the following parameters:
[tex]x \to 2[/tex]
[tex]y \to 1[/tex]
So, the expression is:
[tex]2x + y[/tex] --- (1)
For the electronic assembly (hours), we have the following parameters:
[tex]x\to 2[/tex]
[tex]y \to 3[/tex]
So, the expression is:
[tex]2x + 3y[/tex] --- (2)
Solving further [Time available]:
[tex]General\ Assembly \to 500[/tex]
[tex]Electronic\ Assembly \to 800[/tex]
So, (1) and (2) becomes:
[tex]2x + y \le 500[/tex]
[tex]2x + 3y \le 800[/tex]
Constraints for selling:
[tex]Full\ Size \to 220[/tex] --- at most
[tex]Compact \to 180[/tex] -- at most
The above can be represented as:
[tex]x \le 220[/tex]
[tex]y \le 180[/tex]
Earnings contribution:
[tex]Total\ Full\ Size \to 120[/tex]
[tex]Total\ Compact \to 130[/tex]
The objective function to be maximized can then be modelled as:
[tex]Z = 120x + 130y[/tex]