Answer:
[tex]P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}[/tex]
Step-by-step explanation:
Given
[tex]Cube = \{1,2,3,4,5,6\}[/tex]
[tex]n(Cube) = 6[/tex]
[tex]Spinner = \{A,B,C,D,E,F,G,H\}[/tex]
[tex]n(Spinner) = 8[/tex]
See attachment for spinner
Required
[tex]P(Cube \ge 5\ and\ Spin[A])[/tex]
On a number cube, we have:
[tex]Cube \ge 5 = \{5,6\}[/tex] ---- i.e. 2 outcomes
So, the probability is:
[tex]P(Cube \ge 5) = \frac{n(Cube \ge 5)}{n(Cube)}[/tex]
[tex]P(Cube \ge 5) = \frac{2}{6}[/tex]
[tex]P(Cube \ge 5) = \frac{1}{3}[/tex]
On the spinner, we have:
[tex]Spin [A] = \{A\}[/tex] ---- i.e. 1 outcomes
So, the probability is:
[tex]P(Spin[A]) = \frac{n(Spin[A])}{n(Spinner)}[/tex]
[tex]P(Spin[A]) = \frac{1}{8}[/tex]
[tex]P(Cube \ge 5\ and\ Spin[A])[/tex] is calculated as thus:
[tex]P(Cube \ge 5\ and\ Spin[A]) = P(Cube \ge 5) * P(Spin[A])[/tex]
[tex]P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{3} * \frac{1}{8}[/tex]
[tex]P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}[/tex]