Respuesta :

Nayefx

Answer:

[tex] \displaystyle 8201[/tex]

Step-by-step explanation:

we are given a function that represents the growth of the population

[tex] \displaystyle p(t) = 50 {e}^{0.85t} [/tex]

we want to figure out what the population will be in 2015

since the function is for the population growth after 2009 so the t should be

  • 2015-2009
  • 6

now plug in the value of t:

[tex] \displaystyle p(6) = 50 {e}^{0.85 \times 6} [/tex]

simplify which yields:

[tex] \displaystyle p(6) \approx 8201[/tex]

hence,

in 2015 the population will be 8201

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