Question

find the zeros of the quadratic equation-
v(5v-7)=0

Answer 1

Answer:

Step-by-step explanation:

v(5v-7)=0

We multiply parentheses

5v^2-7v=0

a = 5; b = -7; c = 0;

Δ = b2-4ac

Δ = -72-4·5·0

Δ = 49

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

v1 = −b−√Δ/2a

v2 = -b+√Δ/2a

√Δ = √49 = 7

v1 = -(−7)−7/2*5 = 0/10 = 0

v2 = -(−7)+7/2*5 = 14/10 =  1+2/5

Answer 2

$\huge\text{Hey there!}$

$\huge\textbf{We start off with this current equation:}$

$\mathbf{v(5v - 7) = 0}$

$\huge\textbf{Solving for the answer to your question:}$

$\mathbf{v(5v - 7) = 0}$

$\huge\textbf{Convert your current equation to:}$

$\mathbf{1v(5v - 7) = 0}$

$\huge\textbf{Distribute v or 1 within the parentheses:}$

$\mathbf{\rightarrow 1v(5v) + 1v(-7) = 0}$

$\mathbf{\rightarrow 5v^2 - 7v = 0}$

$\huge\textbf{Factor the left side of the equation:}$

$\mathbf{v(5v - 7) = 0}$

$\huge\textbf{Fator each of the sides to equal to 0:}$

$\mathbf{v = 0\ OR\ as\ in\ 5v - 7 = 0 }$

$\huge\textbf{Simplify the current equation above:}$

$\mathbf{v = 0\ or\ v = \dfrac{7}{5}}$

$\huge\textbf{Thus, the answer should most likely be:}$

$\huge\boxed{\mathsf{v = 0\ or\ v = \dfrac{7}{5}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~$\frak{Amphitrite1040:)}$