Question

A gas has the volume of 45mL at 25 C is heated to 50 C. What is the new volume of the gas? P1V1 = P2V2 V1/T1 = V2/T2 PV = nRT V1/T1 x V2/T2​

Answer 1

Answer:

Option b (V1/T1 = V2/T2) is the right alternative or the new volume will be "0.048 L".

Explanation:

The given values are:

Temperature,

T₁ = 25°C

or,

   = 298.15 K

T₂ = 50°C

or,

    = 323.15 K

Volume,

V₁ = 45 mL

or,

    = 0.045 L

V₂ = ?

As we know,

⇒  $\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Or,

⇒  $V_2=\frac{V_1\times T_2}{T_1}$

On substituting the values, we get

⇒       $=\frac{0.045\times 323.15}{298.15}$

⇒       $=\frac{14.541}{298.15}$

⇒       $=0.048 \ L$