Write the equation of the line that is perpendicular to y=2x-7 and passes through the point (6, 5)
A. y=2x-2
B.y= -1/2x+8
C.y=-1/2x-8
D.y=2x=2

Respuesta :

Nayefx

Answer:

B

Step-by-step explanation:

we are given a equation of a line

we want to figure out the equation of the perpendicular line passes through the (6,5) points

in order to do so

recall that,

[tex] \displaystyle m_{ \text{perpendicular}} = - \frac{1}{m} [/tex]

we got from our given equation that m=2

because equation of a line is y=mx+b

thus

[tex] \displaystyle m_{ \text{perpendicular}} = - \frac{1}{2} [/tex]

remember that, when we want to figure out perpendicular line or parallel line we should the formula given by

[tex] \displaystyle y - y_{1} = m(x - x_{1})[/tex]

since we got our perpendicular m is -½, [tex]x_1=6[/tex] and [tex]y_1=5[/tex], substitute

[tex] \displaystyle y - 5 = - \frac{1}{2} (x - 6)[/tex]

to get the perpendicular equation you should simplify the above equation to y=mx+b form

distribute -½:

[tex] \displaystyle y - 5 = - \frac{1}{2} x + 3[/tex]

add 5 to both sides:

[tex] \displaystyle y = - \frac{1}{2} x + 8[/tex]

hence,

our answer choice is B

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