Question

On a basketball court there is a semicircle above the free throw line that has a radius of 7 find the area of semicircle

Answer 1

Answer: $77\ \text{sq. units}$

Step-by-step explanation:

Given

The radius of the semi-circle is $r=7$

We know, area of the circle is $\pi r^2$

So, the area of the semi-circle is half of it i.e. $\frac{1}{2}\pi r^2$

Put the value

$\Rightarrow \dfrac{1}{2}\times\pi \times 7^2=76.97\\\Rightarrow \approx 77\ \text{sq. units}$

The area of the semi-circle is $77\ \text{sq. units}$