Complete question :
Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation. If y varies inversely as the square of x, and y= 1/8 when x=1, find y when x=5
Answer:
k = 1/8
y = 1 / 200
Step-by-step explanation:
Let the constant of variation = k
y varies inversely as the square of x
y α 1/x²
y = k * 1/x²
y = k/x²
y = 1/8 ; x = 1
1/8 = k/1²
1/8 = k
K = 1/8
y ; when x = 5
y = (1/8 ÷ 5²)
y = 1/8 * 1/5²
y = 1/8 * 1/25
y = 1 / 200
