Question

What is the radius of the circle with equation (x+1/5)^2+(y-2/5)^2=1/25

Answer 1

Answer:

r = $\frac{1}{5}$

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + $\frac{1}{5}$ )² + (y - $\frac{2}{5}$ )² = $\frac{1}{25}$ ← is in standard form

with r² = $\frac{1}{25}$ , then

r = $\sqrt{\frac{1}{25} }$ = $\frac{1}{5}$

Answer 2

The radius of the circle is, r = 1/5 units.

What is equation of circle?

An equation of circle with center (h, k) and radius 'r' is,

(x - h)²+(y - k)² = r²

For given example,

the equation of the circle is, (x+1/5)^2+(y-2/5)^2=1/25

By comparing with standard equation of circle (x - h)²+(y - k)² = r²,

we have h = -1/5, k = 2/5 and r² = 1/25

We need to find the radius of the circle,

r² = 1/25

By taking square-root,

we have r = 1/5 units

Therefore, the radius of the circle is r = 1/5 units.

Learn more about equation of circle here:

https://brainly.com/question/10618691

#SPJ2