Given:
In triangle WXY, [tex]m\angle W=90^\circ, WX=8, XY=17, WY=15[/tex].
To find:
The Cotangent of [tex]\angle X[/tex].
Solution:
In a right angle triangle,
[tex]\cot \theta=\dfrac{Base}{Perpendicular}[/tex]
It can be written as:
[tex]\cot \theta=\dfrac{Adjacent}{Opposite}[/tex]
For triangle WXY,
[tex]\cot (\angle X)=\dfrac{WX}{WY}[/tex]
[tex]\cot (\angle X)=\dfrac{8}{15}[/tex]
Therefore, the Cotangent of [tex]\angle X[/tex] is [tex]\dfrac{8}{15}[/tex].
