Graph the ordered pairs for y = 4x + 2 using x=[-2,1,2]
I don't remember how to do this properly, can someone walk me through it please?

I'm thinking that I need to take (-2,1,2) and plug them into the equation, but what do I do from there?

Respuesta :

to plot the eqution you should solve the values of y with each corresponding values of x.

at x = 1

y = 4x + 2

y = 4(1) + 2 = 6

at x = -2

y = 4(-2) + 2

y = -6

at x = 2

y = 4(2) + 2

y = 10

ANSWER

See graph

EXPLANATION

First you need to substitute each x-value in to the function and calculate for the y-values as follows,

When
[tex]x = - 2[/tex]

[tex]y = 4( - 2) + 2[/tex]

[tex]y = - 8 + 2 = - 6[/tex]

This gives us the ordered pairs,

[tex](-2,-6)[/tex]

When
[tex]x = 1[/tex]

[tex]y = 4(1) + 2[/tex]

[tex]y = 4 + 2 = 6[/tex]
We again have the ordered pair,

[tex](1,6)[/tex]

When
[tex]x = 2[/tex]

[tex]y = 4(2) + 2[/tex]

[tex]y = 8 + 2 = 10[/tex]

This also gives the ordered pair,

[tex]
(2,10)[/tex]

We now plot all the ordered pairs and draw a straight line through the graph as shown in the attachment.
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