Question

Solve 3y^3 + 12y^2 + 12y =0

Please

Answer 1

Answer:

y = 0, -2

Step-by-step explanation:

Factor out the common term 3y.

$3y( {y}^{2} + 4y + 4) = 0$

Rewrite y² + 4y + 4 in the form of a² + 2ab + b², where a = y and b = 2.

$3y( {y}^{2} + 2(y)(2) + {2}^{2} ) = 0$

Use square sum: (a + b)² = a² + 2ab + b².

$3y(y + 2) ^{2} = 0$

solve for y.

y = 0, -2.

therefor, the answer for this equation is 0, - 2.