Answer:
75 sq units
Step-by-step explanation:
A = lw
l = OP = distance between (9, 6) and (0, -6)
= [tex]\sqrt{(9 - 0)^{2} + (6 + 6)^{2} }[/tex]
= [tex]\sqrt{81 + 144)} = \sqrt{225} = 15[/tex]
w = MP = distance between (-4, -3) and (0, -6)
= [tex]\sqrt{(-4 - 0)^{2} + (-3 + 6)^{2} }[/tex]
= [tex]\sqrt{16 + 9} = \sqrt{25} = 5[/tex]
A = 15(5) = 75 sq units
