Question

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 21 fts. The ball's height h (in feet) after seconds is given by the following.

Answer 1

Answer:

h(t)=

h(t)=vt-21t+2

Step-by-step explanation:

initial height =2

initial velocity=21ft/s

dh/dt=v

dh=vdt

intergrating both sides

h(t)-h(i)=vt-v(i)t

h(t)-2=vt-21t

h(t)=vt-21t+2