Question

When the function is given in vertex form y=a(x-h)2+k, how is the vertex found?

Answer 1

Once you have it in that form, you just read off the values of h and k

For instance, if you had y = 2(x-3)^2 + 5, then h = 3 and k = 5. So the vertex is (h,k) = (3,5)

Answer 2

Answer:

Given function is $y=a(x-h)^2+k$ ...........(1)

We re write the function,

transfer k to LHS,

$y-k=a(x-h)^2$

Since, One variable has degree 2 and one variable has degree 1.

⇒ Function Represent the equation of Parabola.

In given Function,

Coordinates of vertex is ( h , k )

So To, find the vertex of the function.

First we rewrite the function in vertex form that is like equation (1) then we compare them and write the coordinate of the vertex.

For Example,

1. y = 2(x - 2)² + 6 then vertex of the function is ( 2 , 6 )

2. y = -3 ( x + 3 )² - 6

    y = - 3 ( x - (-3) )² + ( -6) then vertex of the function is ( -3 , -6 )