Answer:
[tex]x^{2}[/tex]+ [tex]y^{2}[/tex] -4x+2y-7=0
Step-by-step explanation:
Given that, center at (2,-1)
let a = 2, b = -1
radius, r = [tex]\sqrt{12}[/tex]
As we know the equation circle is, [tex](x-a) ^{2}[/tex]+[tex](y-b) ^{2}[/tex] = [tex]r^{2}[/tex] when radius and center point is given.
By this formula , we can get,
[tex](x-2) ^{2}[/tex]+[tex](y-(-1)) ^{2}[/tex] = [tex]\sqrt{12} ^{2}[/tex]
[tex]x^{2}[/tex] -4x +4 + [tex]y^{2}[/tex] + 2y + 1 = 12
[tex]x^{2}[/tex]+ [tex]y^{2}[/tex] -4x+2y-7=0
This is the answer.
