The curved part of this figure is a semicircle.

What is the best approximation for the area of this figure?


10.5+7.25π units²

21+7.25π units²

10.5+14.5π units²

21+14.5π units²

The curved part of this figure is a semicircle What is the best approximation for the area of this figure 105725π units 21725π units 105145π units 21145π units class=

Respuesta :

Answer:

Step-by-step explanation:

Draw the diameter from point (-1, -5) to point (2, 3).

The triangle has base 3 and height 8.

The diameter of the semicircle is the hypotenuse of the triangle.

The radius is half the diameter.

The total area is the area of the triangle plus the area of the semicircle.

 

Answer:

A) 10.5+7.25[tex]\pi[/tex]units²

Step-by-step explanation:

This can be divided into a semicircle and a right triangle.

The area of the right triangle is (1/2)(7)(3)= 10.5

the radius of the semicircle is

[tex]d=\sqrt{7^{2} +3^{2} } )=\sqrt{(49+9)} =\sqrt{58}[/tex]

[tex]r=(1/2)(\sqrt{58}[/tex]

[tex]A=(1/2\pi (1/2)(\sqrt{58)^{2} }[/tex]

[tex]A=58\pi /8[/tex]

[tex]A=7.25\pi[/tex]

[tex]---------[/tex]

hope it helps..

have a great day!!

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