Question

The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
Determine the mass of water in the kettle.
Use Figure 10.
Give your answer to 2 significant figures.
Any help would be appreciated

Answer 1

Answer:

0.37 kg

Explanation:

I'm not a professor myself, but this is how I worked it out:

using the graph, after 100 seconds, the temperature is 100 degrees Celsius.

If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:

4200 = 155000/(m x 100)

If we rearrange and solve for m, we get 0.37 kg.

I'm not sure if I have done this correctly, feel free to correct me.

Hope this helps!

Answer 2

By using the specific heat capacity formula, the  mass of water in the kettle is 0.47 kg

Give that the energy transferred to the water in 100 seconds was 155 000 J and the specific heat capacity of water = 4200 J/kg °C

From the graph;

The initial temperature of the water at time zero is 22 degree Celsius

The final temperature of the water at time 100s is 100 degree Celsius

Change in temperature (T) = 100 - 22 = 78 degree Celsius

To determine the mass of water in the kettle, use the heat energy formula below

E = mcT

Substitute all the parameters into the equation

155000 = 4200 x 78 M

Make M the subject of the formula

M = 155000/327600

M = 0.47 kg

Therefore, the  mass of water in the kettle is 0.47 kg

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