Question

Two numbers have sum of 100 and a difference of 6

Answer 1

The answer to your question is 53 and 47

Answer 2

Answer:

a + b = 100

a - b = 6

2a = 106

2a/2 = 106/2

a = 53

53 + b = 100

53 + b - 53 = 100 - 53

b = 47