Question

Solve this quadratic equation

Answer 1

Answer:

https://www.symbolab.com/solver/step-by-step/x%5E%7B2%7D%20%2B5x%2B3%3D0

Step-by-step explanation:

Answer 2

Answer:

$x = \frac{-5\pm\sqrt{13}}{2}$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the Quadratic Formula.

Standard form of a Quadratic: $ax^2 + bx +c= 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our equation: $x^2+5x+3 = 0$

• a = 1
• b = 5
• c = 3

Plug it into the formula and solve:

• $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
• $x = \frac{-5\pm\sqrt{5^2 - 4(1)(3)}}{2(1)}$
• $x = \frac{-5\pm\sqrt{25-12}}{2}$
• $x = \frac{-5\pm\sqrt{13}}{2}$

This cannot be simplified further. The answer is $x = \frac{-5\pm\sqrt{13}}{2}$.