Question

which equation describes the line that passes through the point (-3,-2) and is parallel to the line 6x+5y=6

Answer 1

Answer:

y = -6/5x - 5.6

Step-by-step explanation:

6x + 5y = 6

-6x          -6x

5y = -6x + 6

/5y    /5y

y = -6/5y + b

-2 = -6/5(-3) + b

-5.6 = b

Answer 2

The equation of line passing through the point (-3,-2) and parallel to line 6x+5y=6 is  6x+5y = -28.

What is equation of line?

Equation of line is a linear equation with a degree of one. The equation of line can be formed with the help of the slope of line and a point on the line.

The general form of the equation of a line  with the slope 'm' and passing through the point

$(y-y_{1}) = m(x-x_{1} )$                          

(where $(x_{1} ,y_{1} )$ is a point through which a  line is passing)

According to the question

We have

A equation of line 6x+5y=6

and, a point (-3,-2)

so, the slope of the line 6x+5y=6

⇒$5y=6x-6$

⇒ $y=\frac{-6}{5} x +\frac{6}{5}$  

the  slope of the line 6x+5y=6 is $\frac{-6}{5}$

Therefore, the equation of line which is parallel to the line 6x+5y=6 and passing through the point (-3, -2) is given by

$(y-y_{1} )=m(x-x_{1} )$

⇒$(y-(-2))=\frac{-6}{5} (x-(-3))$            (slope of the parallel lines are equals)

⇒$(y+2)=\frac{-6}{5}(x+3)$

⇒ $5y+10=-6x-18$

⇒$5y+6x=-28$

⇒$5y+6x+28=0$ or $6x+5y=-28$

Hence, equation of line which is passing through (-3,-2) and parallel to line 6x+5y=6 is 6x+5y=-28.

Learn more about equation of lines here:https://brainly.in/question/6839337

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