Question

If the mass defect for a radionuclide is –8.7839×10-30 kg, what's the binding energy per atom?
Question 7 options:

A)

–7.8944×10-13 J/atom

B)

–4.76×1011 J/atom

C)

–7.8944×10-13 kJ/atom

D)

7.8944×10-13 J/atom

Answer 1

Answer:

A) –7.8944×10-13 J/atom

Explanation:

Mass defect of a radionuclide (m)

$=-8.7839$×$10^{-30} kg$

Formula for binding energy

$E=mc^{2}$

   $=(-8.7839x10^{-30} kg)(3x10^{8} m/s)^{2}$

$E=-7.8944x10^{-13} J/atom$

Answer 2

If the mass defect for a radionuclide is – 8.7839 × 10⁻³° kg, the binding energy per atom will be –7.8944 × 10⁻¹³  J/atom. The correct option is A.

What is radionuclide?

A radionuclide is an unstable nuclide because it contains so much charge. The excess energy is used by the gamma radiation by the nucleus, the electron uses energy to move to another orbital.

Radionuclides are particles that are used to scanning or monitor the radioactive chemicals that are in the body due to swallowing or inhaling.

The binding energy per atom can be calculated by the formula

The mass of defect of a radionuclide (m) is – 8.7839 × 10⁻³° kg

E = mc²

E =  – 8.7839 × 10⁻³° x 3 x 10⁸ m/s

E = –7.8944 × 10⁻¹³  J/atom.

Thus, the correct option is A. –7.8944×10-13 J/atom.

To learn more about radionuclides, refer to the link:

https://brainly.com/question/14605156

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