Find the erea of the trapezoid.

Answer:
[tex]40 {in}^{2} [/tex]
Step-by-step explanation:
[tex]area = \frac{1}{2} (10 + 6) \times 5 \\ = \frac{1}{2} \times 16 \times 5 \\ = 40 {in}^{2} [/tex]
hope this helps you
can I have the brainliest please?
Answer:
40in²
Step-by-step explanation:
area of a trapezoid = [tex]\frac{a+b}{2} h[/tex]
where a and b = bases and h = height
the trapezoid has the following dimensions
base 1 = 10 in
base 2 = 6 in
height = 5 in
Using this information, we plug in the values into the formula
So...
[tex]A=\frac{6+10}{2} 5\\6+10=16\\\frac{16}{2} =8\\8*5=40[/tex]
Hence the area of the trapezoid is 40 in squared