Question

Circle A is located at (6, 5) and has a radius of 3 units. What is the equation of a line that is tangent to circle A from point C (9, 8)?

y = −x + 14
x = 9
y = x − 1
x = 4

Answer 1

Answer:

2nd

Step-by-step explanation:

     

Answer 2

The equation of a line that is tangent to circle A from point C (9, 8) will be option C; y = x − 1.

How to get straight line equation?

If the slope of a line is m and the y-intercept is c, then the equation of that straight line is given as:

y = mx +c

Given; Circle A is located at (6, 5) and has a radius of 3 units.

The slope;

m = (8- 5)/(9 -6) = 1

Substitute in the equation of line;

y = mx +c

8 = 1(9) + c

8 - 9 = c

c = -1

So, We get

y = x − 1

Hence the equation of a line that is tangent to circle A from point C (9, 8) will be option C; y = x − 1.

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