Respuesta :

The answer is 2(x - 1)(x - 6)

Let A be the equivalent numerator: [tex] \frac{A}{(x-2)(x-1)(x-6)} [/tex]

If [tex] \frac{2}{x-2} =\frac{A}{(x-2)(x-1)(x-6)}[/tex],
then: [tex]A = \frac{2(x-2)(x-1)(x-6)}{(x-2)} [/tex]

(x-2) can be cancelled: [tex]A = \frac{2(x-2)(x-1)(x-6)}{(x-2)}= 2(x-1)(x-6)[/tex]



Answer:

The required numerator is 2x²-14x+12 OR 2(x-1)(x-6)

Step-by-step explanation:

Considering the equivalent of the ratio of numerator and denominator to be 2/(x-2), we have to find numerator for given denominator.

Let numerator is A:

then:

[tex]\frac{2}{x-2}=\frac{A}{(x-2)(x-1)(x-6)}  \\[/tex]

cancelling (x-2) from both sides:

[tex]2=\frac{A}{(x-1)(x-6)}[/tex]

Multiplying numerator of A on left side:

[tex]2(x-1)(x-6)=A\\2(x^{2}-7x+6)=A\\2x^{2}-14x+12=A[/tex]

Hence,

The required numerator is 2x²-14x+12 OR 2(x-1)(x-6)

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