Respuesta :
The answer is 2(x - 1)(x - 6)
Let A be the equivalent numerator: [tex] \frac{A}{(x-2)(x-1)(x-6)} [/tex]
If [tex] \frac{2}{x-2} =\frac{A}{(x-2)(x-1)(x-6)}[/tex],
then: [tex]A = \frac{2(x-2)(x-1)(x-6)}{(x-2)} [/tex]
(x-2) can be cancelled: [tex]A = \frac{2(x-2)(x-1)(x-6)}{(x-2)}= 2(x-1)(x-6)[/tex]
Let A be the equivalent numerator: [tex] \frac{A}{(x-2)(x-1)(x-6)} [/tex]
If [tex] \frac{2}{x-2} =\frac{A}{(x-2)(x-1)(x-6)}[/tex],
then: [tex]A = \frac{2(x-2)(x-1)(x-6)}{(x-2)} [/tex]
(x-2) can be cancelled: [tex]A = \frac{2(x-2)(x-1)(x-6)}{(x-2)}= 2(x-1)(x-6)[/tex]
Answer:
The required numerator is 2x²-14x+12 OR 2(x-1)(x-6)
Step-by-step explanation:
Considering the equivalent of the ratio of numerator and denominator to be 2/(x-2), we have to find numerator for given denominator.
Let numerator is A:
then:
[tex]\frac{2}{x-2}=\frac{A}{(x-2)(x-1)(x-6)} \\[/tex]
cancelling (x-2) from both sides:
[tex]2=\frac{A}{(x-1)(x-6)}[/tex]
Multiplying numerator of A on left side:
[tex]2(x-1)(x-6)=A\\2(x^{2}-7x+6)=A\\2x^{2}-14x+12=A[/tex]
Hence,
The required numerator is 2x²-14x+12 OR 2(x-1)(x-6)