Respuesta :
methanol:
1 mole CH3 OH --> produces --> 1 mole CO2
1 mole CO2 has a molar mass of 44.01 gh/mole
your set up is:
(44.01 g CO2) / -726.5kJ = 0.06058g
your answer 0.06058 grams of CO2 produced per kJ released.
1 mole CH3 OH --> produces --> 1 mole CO2
1 mole CO2 has a molar mass of 44.01 gh/mole
your set up is:
(44.01 g CO2) / -726.5kJ = 0.06058g
your answer 0.06058 grams of CO2 produced per kJ released.
The method for calculation of the mass of CO2 emitted per Kj of heat produced in a combustion reaction has been explained below..
To answer this, let us use the combustion reaction of methanol which is;
CH3OH (l) + (3/2)O2 (g) = CO2 (g) + 2H2O (g)
We can find the enthalpy of combustion of this reaction from tables or it will be given to us. Let us use; ΔH = -638.54 KJ
This means for every 1 mole of CO2, the heat released is -638.54 KJ
Now, Molar mass of CO2 is 44 g/mol
Thus;
Mass of CO2 per Kj of heat produced is;
44 g/mol × 1 mol/-638.54 KJ
>> 6.89 × 10^(-2) g/kJ
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