Respuesta :

 methanol:

1 mole CH3 OH --> produces --> 1 mole CO2 

1 mole CO2 has a molar mass of 44.01 gh/mole
 
your set up is:
(44.01 g CO2) / -726.5kJ = 0.06058g

your answer 0.06058 grams of CO2 produced per kJ released.

The method for calculation of the mass of CO2 emitted per Kj of heat produced in a combustion reaction has been explained below..

To answer this, let us use the combustion reaction of methanol which is;

CH3OH (l) + (3/2)O2 (g) = CO2 (g) + 2H2O (g)

We can find the enthalpy of combustion of this reaction from tables or it will be given to us. Let us use; ΔH = -638.54 KJ

This means for every 1 mole of CO2, the heat released is -638.54 KJ

Now, Molar mass of CO2 is 44 g/mol

Thus;

Mass of CO2 per Kj of heat produced is;

44 g/mol × 1 mol/-638.54 KJ

>> 6.89 × 10^(-2) g/kJ

Read more at; https://brainly.com/question/12996596

ACCESS MORE
EDU ACCESS
Universidad de Mexico