Question

yall this one too i need help quick guys plz and ty

Answer 1

Answer:

b. (4,2)

Step-by-step explanation:

step one: isolate x in the first equation

substitute x=6-y: $\begin{bmatrix}2\left(6-y\right)-2y=4\end{bmatrix}$

$\begin{bmatrix}12-4y=4\end{bmatrix}$

$-4y=-8$

$y=2$

step two: isolate y in the second equation, substitute y=2

$x=6-y$

$x=6-2$

$x=4$

Answer 2

Answer:

b

Step-by-step explanation:

Given the 2 equations

3x + 3y = 18 → (2)

2x - 2y = 4 → (2)

Multiplying (1) by 2 and (2) by 3 and adding the result will eliminate the y- term

6x + 6y = 36 → (3)

6x - 6y = 12 → (4)

Add (3) and (4) term by term to eliminate y

12x + 0 = 48

12x = 48 ( divide both sides by 12 )

x = 4

Substitute x = 4 into either of the 2 equations and solve for y

Substituting into (1)

3(4) + 3y = 18

12 + 3y = 18 ( subtract 12 from both sides )

3y = 6 ( divide both sides by 3 )

y = 2

solution is (4, 2 ) → b