Answer:
m∠G = 31.83°
Step-by-step explanation:
From the triangle FGH,
FH = 6 ft
FG = 11 ft
And measure of the included angle ∠F = 73°
We have to find the measure of ∠G.
By applying law of cosine in the triangle to get the measure of third side GH first,
GH² = FH² + FG² - 2(FH)(FG)cos(∠F)
GH² = 6² + 11² - 2(6)(11)cos(73°)
GH² = 36 + 121 - 38.593
GH = √118.407
GH = 10.88 ft
Now apply sine rule in the given triangle to get the measure of ∠G.
[tex]\frac{\text{sinG}}{FH}=\frac{\text{sinF}}{GH}[/tex]
[tex]\frac{\text{sinG}}{6}= \frac{\text{sin(73)}}{10.88}[/tex]
sin(G) = 0.527374
G = [tex]\text{sin}^{-1}(0.527374)[/tex]
m∠G = 31.83°
